io_uring/io-wq: ignore non-busy worker going to sleep
When an io-wq worker goes to sleep, it checks if there's work to do. If there is, it'll create a new worker. But if this worker is currently idle, it'll either get woken right back up immediately, or someone else has already created the necessary worker to handle this work. Only go through the worker creation logic if the current worker is currently handling a work item. That means it's being scheduled out as part of handling that work, not just going to sleep on its own. Signed-off-by: Jens Axboe <axboe@kernel.dk>pull/1250/head
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@ -429,6 +429,8 @@ static void io_wq_dec_running(struct io_worker *worker)
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if (!atomic_dec_and_test(&acct->nr_running))
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if (!atomic_dec_and_test(&acct->nr_running))
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return;
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return;
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if (!worker->cur_work)
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return;
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if (!io_acct_run_queue(acct))
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if (!io_acct_run_queue(acct))
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return;
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return;
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